x^2/3-5=4x^1/3

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Solution for x^2/3-5=4x^1/3 equation: 


x in (-oo:+oo)

(x^2)/3-5 = (4*x^1)/3 // - (4*x^1)/3

(x^2)/3-((4*x^1)/3)-5 = 0

(x^2)/3+(-4/3)*x-5 = 0

1/3*x^2-4/3*x-5 = 0

DELTA = (-4/3)^2-(-5*1/3*4)

DELTA = 76/9

DELTA > 0

x = ((76/9)^(1/2)+4/3)/(1/3*2) or x = (4/3-(76/9)^(1/2))/(1/3*2)

x = 3/2*((76/9)^(1/2)+4/3) or x = 3/2*(4/3-(76/9)^(1/2))

x in { 3/2*(4/3-(76/9)^(1/2)), 3/2*((76/9)^(1/2)+4/3) }

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